diff --git a/ap/build/uClibc/libc/stdlib/lldiv.c b/ap/build/uClibc/libc/stdlib/lldiv.c
new file mode 100644
index 0000000..ff67017
--- /dev/null
+++ b/ap/build/uClibc/libc/stdlib/lldiv.c
@@ -0,0 +1,61 @@
+/* `long long int' divison with remainder.
+   Copyright (C) 1992, 1996, 1997 Free Software Foundation, Inc.
+   This file is part of the GNU C Library.
+
+   The GNU C Library is free software; you can redistribute it and/or
+   modify it under the terms of the GNU Lesser General Public
+   License as published by the Free Software Foundation; either
+   version 2.1 of the License, or (at your option) any later version.
+
+   The GNU C Library is distributed in the hope that it will be useful,
+   but WITHOUT ANY WARRANTY; without even the implied warranty of
+   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
+   Lesser General Public License for more details.
+
+   You should have received a copy of the GNU Lesser General Public
+   License along with the GNU C Library; if not, write to the Free
+   Software Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA
+   02111-1307 USA.  */
+
+#include <features.h>
+#include <stdlib.h>
+
+
+/* Return the `lldiv_t' representation of NUMER over DENOM.  */
+lldiv_t
+lldiv (long long int numer, long long int denom)
+{
+    lldiv_t result;
+
+    result.quot = numer / denom;
+    result.rem = numer % denom;
+
+    /* The ANSI standard says that |QUOT| <= |NUMER / DENOM|, where
+       NUMER / DENOM is to be computed in infinite precision.  In
+       other words, we should always truncate the quotient towards
+       zero, never -infinity.  Machine division and remainer may
+       work either way when one or both of NUMER or DENOM is
+       negative.  If only one is negative and QUOT has been
+       truncated towards -infinity, REM will have the same sign as
+       DENOM and the opposite sign of NUMER; if both are negative
+       and QUOT has been truncated towards -infinity, REM will be
+       positive (will have the opposite sign of NUMER).  These are
+       considered `wrong'.  If both are NUM and DENOM are positive,
+       RESULT will always be positive.  This all boils down to: if
+       NUMER >= 0, but REM < 0, we got the wrong answer.  In that
+       case, to get the right answer, add 1 to QUOT and subtract
+       DENOM from REM.  */
+
+    if (numer >= 0 && result.rem < 0)
+    {
+	++result.quot;
+	result.rem -= denom;
+    }
+
+    return result;
+}
+
+#if __WORDSIZE != 64
+#undef imaxdiv
+strong_alias(lldiv,imaxdiv)
+#endif